Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
8
Rotational Motion
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8-1: Angular Quantities
8-2 and 8-3: Constant Angular Acceleration; Rolling
8-4: Torque
8-5 and 8-6: Rotational Dynamics
8-7: Rotational Kinetic Energy
8-8: Angular Momentum
8-9: Angular Quantities as Vectors

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 5
Q

The platter of the hard drive of a computer rotates at 7200 rpm (rpm = revolutions per minute = rev/min).

  1. What is the angular velocity (rad/s) of the platter?
  2. If the reading head of the drive is located 3.00 cm from the rotation axis, what is the linear speed of the point on the platter just below it?
  3. If a single bit requires 0.50  μm0.50 \; \mu \textrm{m} of length along the direction of motion, how many bits per second can the writing head write when it is 3.00 cm from the axis?
A
  1. 750 rad/s750 \textrm{ rad/s}
  2. 23 m/s23 \textrm{ m/s}
  3. 4.5×107 bits/s4.5 \times 10^7 \textrm{ bits/s}
Giancoli 7th Edition, Chapter 8, Problem 5 solution video poster
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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. To convert rpm into radians per second, I find it helpful to remember that rpm is revolutions per minute and writing it this way: rev's with a division sign 'per' and minutes on the bottom and then we can see that if we write 1 minute for every 60 seconds the minutes will cancel and we can multiply by 2π radians— one full circle, in other words— for every revolution and the revolution's cancel leaving us with radians per second. So 7200 times 2π divided by 60 gives 750 radians per second. The linear speed of a point directly underneath the reading head when it's positioned 3 centimeters from the center of the hard drive platter will be 3 times 10 to the minus 2 meters— converting that centimeters into meters— times by the angular velocity of the platter which is 753.98 radians per second and that gives linear speed of a point right under the reading head of 23 meters per second; notice how I use the unrounded number in the calculation to avoid intermediate rounding error. And then if there's a writing head positioned there and it can write 1 bit for every 0.5 micrometers where I have written 0.5 times 10 to the minus 6 meters here and then times that by the speed that the point underneath the writing head is going— linear speed, 22.619 meters per second— the meters cancel and we get 4.5 times 10 to the 7 bits per second.

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