Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
6
Work and Energy
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6-1: Work, Constant Force
6-2: Work, Varying Force
6-3: Kinetic Energy; Work-Energy Principle
6-4 and 6-5: Potential Energy
6-6 and 6-7: Conservation of Mechanical Energy
6-8 and 6-9: Law of Conservation of Energy
6-10: Power

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 30
Q

A 1.60-m-tall person lifts a 1.65-kg book off the ground so it is 2.20 m above the ground. What is the potential energy of the book relative to

  1. the ground, and
  2. the top of the person’s head?
  3. How is the work done by the person related to the answers in parts (a) and (b)?
A
  1. 35.6 J35.6\textrm{ J}
  2. 9.70 J9.70\textrm{ J}
  3. 35.6 J35.6\textrm{ J}
Giancoli 7th Edition, Chapter 6, Problem 30 solution video poster
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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. This person lifts a book, 2.2 meters up into the air; the person's 1.6 meters tall and the separation between the person's head and the book is 2.2 minus 1.6 meters, which is 0.6 meters and we'll need to use this value in part (b) of the question. Part (a) of the question is, "what is the potential energy, relative to the ground?" So that's gonna be mg times height above the ground; the ground is the reference level for part (a). So we have 1.65 kilograms— mass of the book— times 9.8 newtons per kilogram times 2.20 meters which is 35.6 joules of potential energy relative to the ground. Potential energy, relative to the head, is the mg times the height above the head; the head is the reference level now so that's the mass times g times 0.60 meters which is 9.70 joules. And the work done by the person equals the change in potential energy that occurred over the distance during which the force of the person was applied, and the person applied the force beginning at the ground and up to this final height here so it's that change in potential energy that matters and so it has only to do with part (a). Part (b) is not relevant for, as for answering the question of how much work the person did because, yeah, you need to consider the total height over which the person applied the force, which is starting from the ground and going up to this, 2.2 meters above the ground. And so the answer is the same as the answer in part (a); the work done by the person is what's causing this change in potential energy and they do 35.6 joules of work.

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