Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
20

20-3: Force on Electric Current in Magnetic Field
20-4: Force on Charge Moving in Magnetic Field
20-5 and 20-6: Magnetic Field of Straight Wire, Force between Two Wires
20-7: Solenoids and Electromagnets
20-8: Ampère's Law
20-9 and 20-10: Torque on Curent Loop, Motors, Galvanometers
20-11: Mass Spectrometer
20-12: Ferromagnetism, Hysteresis

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 31
Q

A rectangular loop of wire is placed next to a straight wire, as shown in Fig. 20–55. There is a current of 3.5 A in both wires. Determine the magnitude and direction of the net force on the loop.

Problem 31.
Figure 20-55.
A
5.1×106 N, up5.1 \times 10^{-6} \textrm{ N, up}
Giancoli 7th Edition, Chapter 20, Problem 31 solution video poster
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COMMENTS
By merkinthedark on Mon, 4/25/2016 - 8:39 PM

can you check your calculations because I get my answer in the order of 5.0437x10^-7

By Mr. Dychko on Sun, 5/1/2016 - 4:13 AM

Hi merkinthedark, I ran the final numbers shown in the video through the calculator again and confirmed the answer, so please let me know if you find any specific error. It looks fine so far.

Best,
Mr. Dychko

By d.giraldo31 on Fri, 11/5/2021 - 2:03 AM

What is the value of L (length)? is it the total length of the loop only? The value of .1 m seem like just the value of one side

By Mr. Dychko on Tue, 11/9/2021 - 10:33 PM

Hi d.giraldo31, you're totally right: 0.1 m is only the length of the sides of the rectangle parallel to the wire. These two sides are the only ones that are important for the calculation of net force. The two other edges of the rectangle on the sides experience equal magnitude force that are opposite in direction so these forces cancel. The forces on the two parallel segments, on the other hand, while in opposite directions, are not of equal magnitude. The attractive force on the top segment exceeds the repulsion of the bottom segment.
All the best,
Shaun

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