A helium ion (Q = +2e) whose mass is 6.6 x 10^{-27} kg is accelerated by a voltage of 3700 V. a) What is its speed? b) What will be its radius of curvature if it moves in a plane perpendicular to a uniform 0.340-T field? c) What is its period of revolution?

What is its speed?
What will be its radius of curvature if it moves in a plane perpendicular to a uniform 0.340-T field?
What is its period of revolution?

$6.0 \times 10^5 \textrm{ m/s}$
$3.6 \textrm{ cm}$
$3.8 \times 10^{-7} \textrm{ s}$

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A helium ion (Q = +2e) whose mass is 6.6×10−27 kg6.6 \times 10^{-27} \textrm{ kg}6.6×10−27 kg is accelerated by a voltage of 3700 V.

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A helium ion (Q = +2e) whose mass is $6.6 \times 10^{-27} \textrm{ kg}$ is accelerated by a voltage of 3700 V.