Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
16
Electric Charge and Electric Field
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16-5 and 16-6: Coulomb's Law
16-7 and 16-8: Electric Field, Field Lines
16-10: DNA
16-12: Gauss's Law

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 39
Q

In Fig. 16–62, two objects, O1O_1 and O2O_2, have charges +1.0  μC+1.0 \; \mu \textrm{C} and 2.0  μC-2.0 \; \mu \textrm{C}, respectively, and a third object, O3O_3, is electrically neutral.

  1. What is the electric flux through the surface A1A_1 that encloses all three objects?
  2. What is the electric flux through the surface A2A_2 that encloses the third object only?
Problem 39.
Figure 16-62.
A
  1. 1.1×105 N m2/C-1.1 \times 10^5 \textrm{ N m}^2\textrm{/C}
  2. Zero
Giancoli 7th Edition, Chapter 16, Problem 39 solution video poster
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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. The total flux through the surface enclosing all the charges is gonna equal the total enclosed charge divided by permittivity of free space. The total enclosed charge is 1.0 times 10 to the minus six Coulombs positive, plus the negative 2.0 times to the minus six Coulombs. And the third object has no charge, and so it doesn't even enter into this part at all. And we divide it by permittivity of free space, 8.85 times 10 to the minus 12 Coulombs squared per Newton meters squared. And we get negative 1.1 times 10 the five Newton meters squared per Coulomb. And that's the total flux. And the total flux through the surface enclosing the neutral object will be zero because it encloses no charge, no net charge. And zero divided by whatever that is, is still zero.

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