Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
16
Electric Charge and Electric Field
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16-5 and 16-6: Coulomb's Law
16-7 and 16-8: Electric Field, Field Lines
16-10: DNA
16-12: Gauss's Law

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 22
Q

A downward electric force of 6.4 N is exerted on a 7.3  μC-7.3 \; \mu \textrm{C} charge. Find the magnitude and direction of the electric field at the position of this charge.

A
8.8×105 N/C, up8.8 \times 10^5 \textrm{ N/C, up}
Giancoli 7th Edition, Chapter 16, Problem 22 solution video poster
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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. The direction of the electric field is the easiest thing to figure out first of all. Since the negative charge experiences a force downwards, electric field must be pointing upwards because electric field points in the same direction as force that would be exerted on a positive charge, and so it points in the opposite direction to the direction of force on the negative charge. If the force on this negative charge is down, electric field must be going upwards. For the size of the electric field, we can take this formula, force is the charge multiplied by the field strength. And rearrange it for E, divide both sides by q. And the force is 6.4 Newtons divided by the charge of 7.3 times 10 to the minus six Coulombs, this gives us 8.8 times 10 to the five Newtons per Coulomb directed upwards for the electric field.

COMMENTS
By cthomas7 on Sun, 2/27/2022 - 8:23 PM

Why was it a positive number when the charge is negative?

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