Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
17
Electric Potential
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17-1 to 17-4: Electric Potential
17-5: Potential Due to Point Charges
17-6: Electric Dipoles
17-7: Capacitance
17-8: Dielectrics
17-9: Electric Energy Storage
17-10: Digital
17-11: TV and Computer Monitors

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 6
Q

How strong is the electric field between two parallel plates 6.8 mm apart if the potential difference between them is 220 V?

A
3.2×104 N/C3.2 \times 10^4 \textrm{ N/C}
Giancoli 7th Edition, Chapter 17, Problem 6 solution video poster
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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. The strength of the electric field between two parallel plates is the potential difference between the plates divided by the separation. And I put vertical absolute value signs here because we don't care about the sign, we only care about the strength of the field, its magnitude. That's 220 volts divided by 6.8 times 10 the minus three meters separating them. That's 6.8 millimeters written with times 10 to the minus three in place of the prefix milli. We get 32,352 Newtons per Coulomb or 3.2 times 10 to the four Newtons per Coulomb. And you can write Newtons per Coulomb as volts per meter if you like too, that would also work for the units.

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