Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
17
Electric Potential
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17-1 to 17-4: Electric Potential
17-5: Potential Due to Point Charges
17-6: Electric Dipoles
17-7: Capacitance
17-8: Dielectrics
17-9: Electric Energy Storage
17-10: Digital
17-11: TV and Computer Monitors

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 53
Q

A cardiac defibrillator is used to shock a heart that is beating erratically. A capacitor in this device is charged to 5.0 kV and stores 1200 J of energy. What is its capacitance?

A
96μF96\mu\textrm{F}
Giancoli 7th Edition, Chapter 17, Problem 53 solution video poster
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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. The potential energy stored in the capacitor on this defibrillator is one half times its capacitance times the voltage across it, squared. And then we can solve for C by multiplying both sides by two over V squared. And then switching the sides around as well. So on the left we're going to end up with C equals two times potential energy divided by voltage squared so two times 1200 joules divided by 5.0 times ten to the three volts squared which gives about 96 micro farads.

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