Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
17
Electric Potential
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17-1 to 17-4: Electric Potential
17-5: Potential Due to Point Charges
17-6: Electric Dipoles
17-7: Capacitance
17-8: Dielectrics
17-9: Electric Energy Storage
17-10: Digital
17-11: TV and Computer Monitors

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 57
Q

There is an electric field near the Earth’s surface whose magnitude is about 150 V/m. How much energy is stored per cubic meter in this field?

A
1.0×107 J/m31.0 \times 10^{-7} \textrm{ J/m}^3
Giancoli 7th Edition, Chapter 17, Problem 57 solution video poster
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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. Energy density is one half times permittivity of free space times the electric field strength squared that's one half times 8.85 times ten to the minus 12 coulombs squared per newton meter squared times this electric field of 150 volts per meter squared. And this gives an energy density of about 1.0 times ten to the minus seven joules per cubic meter. These exponents are different here because the way things rounded there should be about two significant figures because this number has two significant figures. So 9.95 when you round this number, it makes this number turn into a ten. So ten times ten to the minus eight is our answer. With the zero being significant. And so this is written in scientific notation becomes 1.0 times ten to the minus seven because you know you have to… we will multiply this number by… we'll divide this number by ten to make it 1.0 in which case we have to multiply this by ten so ten to the minus eight times ten to the minus seven.

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