Show that Bernoulli’s equation reduces to the hydrostatic variation of pressure with depth (Eq. 10–3b) when there is no flow .
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This is Giancoli Answers with Mr. Dychko. Here's Bernoulli's equation which says that the pressure at some point down here say plus this term, which is zero because there's no movement in this fluid, plus density times g times the y-coordinate of this position 2 equals the pressure at position 1 plus ρgy 1 as well. And we can subtract P 1 from both sides and we get P 2 minus P 1 on the left and then we move this term to the right side and we get this ρg that we can factor out and we get y 1 minus y 2. Now y 1 minus y 2 is the height of this column of fluid so y 1 is the initial or the top point and y 2 is the bottom point in this fluid column. And so Δh is y 1 minus y 2 so we can substitute that in and we end up with this which is equation that we are looking for... what is that... [10-3b] that the change in pressure is density times g times the height.
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