In order to watch this solution you need to have a subscription.
This is Giancoli Answers with Mr. Dychko. The absolute pressure at the bottom of the pool would be the atmospheric pressure applied to the surface of the pool plus the pressure due to the column of water. And this ΔP is gonna be the density of water times g times the height of the water column which is the depth of the pool, 1.8 meters. So that's 1.8 times 9.8 newtons per kilogram times 1.00 times 10 to the 3 kilograms per cubic meter—density of water— plus atmospheric pressure of 1.013 times 10 to the 5 newtons per square meter gives 1.19 times 10 to the 5 pascals is the absolute pressure. And the force at the bottom of the pool would be that pressure times by the area of the pool bottom which is 28 meters by 8.5 meters that gives a total force of 2.8 times 10 to the 7 newtons. And the pressure against the sides of the pool at the bottom will be the same as the pressure right at the bottom because pressure is not directional— it's the same in all directions including on the bottom and on the sides at the bottom: 1.19 times 10 to the 5 pascals.