Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 6th Edition
2
Describing Motion: Kinematics in One Dimension
Change chapter

2-1 to 2-3: Speed and Velocity
2-4: Acceleration
2-5 and 2-6: Motion at Constant Acceleration
2-7: Falling Objects [neglect air resistance]
2-8: Graphical Analysis

Problem 33
A
51.8m51.8 \textrm{m}
Giancoli 6th Edition, Chapter 2, Problem 33 solution video poster
Padlock

In order to watch this solution you need to have a subscription.

VIDEO TRANSCRIPT

A stone takes three and a quarter seconds to fall from the top of a cliff. We’ll assume that’s its initial speed is zero meters per second because it was dropped and its acceleration is nine point eight meters per second squared and we’ll choose down to be the positive direction. The formula we’ll use is the distance it’s going to cover, the height of the cliff is: initial speed times time plus one half ‘a’ times‘t’ squared, this first term will be zero because there’s no initial velocity meaning that ‘h’ is: one half times nine point eight meters per second squared times three and a quarter seconds all squared which gives a cliff height of fifty one point eight meters. So the next time you’re out hiking you can drop a stone off a cliff and time its length of descent and square your time and multiply it by five approximately and you’ll have an estimate of your height. For the 5th Edition the stone takes three and a half seconds and the cliff height is sixty point zero meters.

Find us on:

Facebook iconTrustpilot icon
Giancoli Answers, including solutions and videos, is copyright © 2009-2024 Shaun Dychko, Vancouver, BC, Canada. Giancoli Answers is not affiliated with the textbook publisher. Book covers, titles, and author names appear for reference purposes only and are the property of their respective owners. Giancoli Answers is your best source for the 7th and 6th edition Giancoli physics solutions.