Question

In a series of decays, the nuclide {^{235}_{92} U } becomes {^{207}_{82} Pb }. How many \alpha and \beta^{-} particles are emitted in this series?

Accepted Answer

7 alpha particles and 4 electrons

In a series of decays, the nuclide ${^{235}_{92}\textrm{U}}$ becomes ${^{207}_{82}\textrm{Pb}}$ . How many $\alpha$ and $\beta^{-}$ particles are emitted in this series?

In a series of decays, the nuclide 92235U{^{235}_{92}\textrm{U}}92235​U becomes 82207Pb{^{207}_{82}\textrm{Pb}}82207​Pb. How many α\alphaα and β−\beta^{-}β− particles are emitted in this series?