Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
24
The Wave Nature of Light
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24-3: Double-Slit Interference
24-4: Visible Spectrum; Dispersion
24-5: Single-Slit Diffraction
24-6 and 24-7: Diffraction Gratings
24-8: Thin-Film Interference
24-9: Michelson Interferometer
24-10: Polarization

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 11
Q

Suppose a thin piece of glass is placed in front of the lower slit in Fig. 24–7 so that the two waves enter the slits 180180 ^\circ out of phase (Fig. 24–58). Draw in detail the interference pattern seen on the screen.

Problem 11.
Figure 24-58.
How the wave theory explains the pattern of lines seen in the double-slit experiment.
Figure 24-7 How the wave theory explains the pattern of lines seen in the double-slit experiment. (a) At the center of the screen, waves from each slit travel the same distance and are in phase. [Assume ldl \gg d.]
How the wave theory explains the pattern of lines seen in the double-slit experiment.
Figure 24-7 How the wave theory explains the pattern of lines seen in the double-slit experiment. (b) At this angle θ\theta, the lower wave travels an extra distance of one whole wavelength, and the waves are in phase; note from the shaded triangle that the path difference equals d sin  θ\textrm{d sin} \; \theta.
How the wave theory explains the pattern of lines seen in the double-slit experiment.
Figure 24-7 How the wave theory explains the pattern of lines seen in the double-slit experiment. (c) For this angle θ\theta, the lower wave travels an extra distance equal to one-half wavelength, so the two waves arrive at the screen fully out of phase.
How the wave theory explains the pattern of lines seen in the double-slit experiment.
Figure 24-7 How the wave theory explains the pattern of lines seen in the double-slit experiment. (d) A more detailed diagram showing the geometry for parts (b) and (c).
A
constructive: dsinθ=λ(m12),m=1,2,3,...d \sin \theta = \lambda \left( m - \dfrac{1}{2} \right), m=1,2,3,...
destructive: dsinθ=mλ,m=0,1,2,3,...d \sin \theta = m \lambda, m = 0,1,2,3,...
The interference pattern is reversed.
Giancoli 7th Edition, Chapter 24, Problem 11 solution video poster
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