Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
1
Introduction, Measurement, Estimating
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1-4: Measurement, Uncertainty, Significant Figures
1-5 and 1-6: Units, Standards, SI, Converting Units
1-7: Order-of-Magnitude Estimating
1-8: Dimensions

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 15
Q

The Sun, on average, is 93 million miles from Earth. How many meters is this? Express

  1. using powers of 10, and
  2. using a metric prefix (km).
A
a) 1.5×1011 m1.5 \times 10^{11} \textrm{ m} Note that the video has an error for part (a) since it uses miles instead of meters. Thanks @kingrhino for spotting that.
b) 1.5×108 km1.5 \times 10^8 \textrm{ km}
Giancoli 7th Edition, Chapter 1, Problem 15 solution video poster
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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. Million gets the prefix 10 to the 6 so we have for part (a), 93 times 10 to the 6 miles could be one way of writing it with power notation. And in part (b), the front cover gives us a conversation factor between kilometers and miles; it's saying it is 1 kilometer for every 0.6214 miles so we multiply 93 times 10 to the 6 miles by this conversion factor and the miles cancel giving us 1.4966 times 10 to the 8 kilometers— the distance to the Sun— and we have two significant figures and so we have 1.5 times 10 to the 8 kilometers.

COMMENTS
By kingrhino on Mon, 5/16/2016 - 10:48 AM

Is part A a mistake? It asked for 93 million miles in meters. I would think that it would be rounded to 1.5 x10^11 meters

By Mr. Dychko on Tue, 5/17/2016 - 3:04 AM

Hi kingrhino, yes, you're quite right that it does ask for meters. I've updated the quick answer and made a note about the mistake in the video. Thanks for the sharp eye.

All the best,
Mr. Dychko

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