Hi jtorres89,

Good question. It is not possible to cancel the m's. Doing so is a common type of algebra mistake. "cancelling" really means dividing every term on the top by the bottom, so if you tried cancelling the m's, you would end up with $\dfrac{F_c}{m} - g$. Notice that, which the m's did cancel from the second term, the 'm' is still hanging around under the Fc term.

Hi,

I'm just wondering, couldn't the m's in the step (Fc-m*g)/m cancel out?

Thanks