Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Global Edition
16
Electric Charge and Electric Field
Change chapter

16-5 and 16-6: Coulomb's Law
16-7 and 16-8: Electric Field, Field Lines
16-10: DNA
16-12: Gauss's Law

Problem 5
A
1.9×1013%1.9 \times 10^{-13} \%
Giancoli 7th "Global" Edition, Chapter 16, Problem 5 solution video poster
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COMMENTS
By Fellspade5390 on Wed, 8/28/2024 - 2:14 PM

When you got 1.898 x 10 ^-15, and then became 1.9 x 10 ^-13, how did it go from the power of -15 to -13.

By Mr. Dychko on Thu, 9/5/2024 - 9:00 PM

Hi Fellspade5390, thank you for the question. When expressing the fractional change 1.898×10151.898 \times 10^{-15} as a percent it's necessary to multiply by 100 since "percent" means divide by 100. In other words percent means the number is expressed as a fraction where the denominator is 100, but the convention is to not write that denominator and write only the percent sign, %, instead. In order for the quantity to remain unchanged after "dividing by 100" (which the percent sign effectively does) it is necessary to multiply the number by 100, hence 1015×100=×101310^{-15} \times 100 = \times 10^{-13}.
Hope this helps,
Shaun

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