Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
7
Linear Momentum
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7-1 and 7-2: Momentum and its Conservation
7-3: Collisions and Impulse
7-4 and 7-5: Elastic Collisions
7-6: Inelastic Collisions
7-7: Collisions in Two Dimensions
7-8: Center of Mass (CM)
7-9: CM for the Human Body
7-10: CM and Translational Motion

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 49
Q

The distance between a carbon atom (m=12 u)(m = 12 \textrm{ u}) and an oxygen atom (m=16 u)(m = 16 \textrm{ u}) in the CO molecule is 1.13×1010 m1.13 \times 10^{-10} \textrm{ m}. How far from the carbon atom is the center of mass of the molecule?

A
6.5×1011 m from the C atom6.5\times 10^{-11} \textrm{ m from the C atom}
Giancoli 7th Edition, Chapter 7, Problem 49 solution video poster
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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. The center of mass for a system with two particles is the mass of the first particle times its distance from some reference point x 1 plus the mass of the second particle times its distance from some reference point divided by the total mass of both particles. So we'll take the position of the carbon atom to be the origin so x 1 is 0— that's gonna be our reference point— and we'll multiply that by the mass of the carbon atom which is 12 atomic mass units although this term is just going to make zero anyway and then add that to the mass of the oxygen atom times its distance from the carbon atom— 1.13 times 10 to the minus 10 meters— and divide that by the total mass 16 plus 12 atomic mass units. This gives us a position for the center of mass as being 6.5 times 10 to the minus 11 meters and since the carbon atom is chosen as a reference point, this distance is from the carbon atom.

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