Question

If {^{6}_{3} Li } is struck by a slow neutron, it can form {^{4}_{2} He } and another nucleus. a) What is the second nucleus? (This is a method of generating this isotope.) b) How much energy is released in the process?

Accepted Answer

a) {}_3^6Li + {}_0^1n \longrightarrow {}_2^4He + {}_1^3H b) 4.784 MeV

If ${^{6}_{3}\textrm{Li}}$ is struck by a slow neutron, it can form ${^{4}_{2}\textrm{He}}$ and another nucleus.

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If 36Li{^{6}_{3}\textrm{Li}}36​Li is struck by a slow neutron, it can form 24He{^{4}_{2}\textrm{He}}24​He and another nucleus.

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If ${^{6}_{3}\textrm{Li}}$ is struck by a slow neutron, it can form ${^{4}_{2}\textrm{He}}$ and another nucleus.