Question

Calculate the kinetic energy and momentum of a proton (m = 1.67 x 10^{-27} kg ) traveling 8.65 x 10^7 m/s . By what percentages would your calculations have been in error if you had used classical formulas?

Accepted Answer

KE = 41.7 MeV, p = 283 MeV/c   % error _{KE} = -6.3 %, % error _p = -4.3 %

Calculate the kinetic energy and momentum of a proton (m = $1.67 \times 10^{-27} \textrm{ kg}$ ) traveling $8.65 \times 10^7 \textrm{ m/s}$ . By what percentages would your calculations have been in error if you had used classical formulas?

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Calculate the kinetic energy and momentum of a proton (m = 1.67×10−27 kg1.67 \times 10^{-27} \textrm{ kg}1.67×10−27 kg) traveling 8.65×107 m/s8.65 \times 10^7 \textrm{ m/s}8.65×107 m/s. By what percentages would your calculations have been in error if you had used classical formulas?

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Calculate the kinetic energy and momentum of a proton (m = $1.67 \times 10^{-27} \textrm{ kg}$ ) traveling $8.65 \times 10^7 \textrm{ m/s}$ . By what percentages would your calculations have been in error if you had used classical formulas?