Giancoli 6th Edition, Chapter 8, Problem 64

Problem 64

KE = 5 \times 0^{16} \textrm{J}

L = 3 \times 10^{20} \textrm{kgm}^2\textrm{/s}

Note: At 3:23 I mention correctly that the angular velocity is

3.333 \times 10^{-4}

, whereas at 3:46 I incorrectly wrote

3.333 \times 10^{-11}

. My calculations were nevertheless done using

3.333 \times 10^{-4}

, so the results are correct. Where you hear

3.333 \times 10^{-11}

, please think:

3.333 \times 10^{-4}

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COMMENTS

By thesouthportschool on Sat, 2/18/2017 - 11:37 PM

Is the answer not 453.6926 J or 5*10^2 J, I copied the exact calculations from your final answer of part A (3:49) and did not get 5*10^16 J.

By thesouthportschool on Sat, 2/18/2017 - 11:43 PM

And I also you changed the angular velocity from 3.333*10^-4 to 3.333*10^-11 when doing the calculations to work out the KE

By Mr. Dychko on Wed, 2/22/2017 - 8:37 AM

Hello student from thesoutportschool, thank you for spotting the error. At 3:23 I mention correctly that the angular velocity is $3.333 \times 10^{-4}$ , whereas at 3:46 I incorrectly wrote $3.333 \times 10^{-11}$ . My calculations were nevertheless done using $3.333 \times 10^{-4}$ , so the results are correct. I'll put a note above the video to use $3.333 \times 10^{-4}$ for the angular velocity.

All the best,
Mr. Dychko

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