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Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 6th Edition
6
Work and Energy
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6-1: Work, Constant Force
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6-3: Kinetic Energy; Work-Energy Principle
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6-4 and 6-5: Potential Energy
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6-6 and 6-7: Conservatino of Mechanical Energy
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6-8 and 6-9: Law of Conservation of Energy
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6-10: Power
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Problem 41
A
12mv2+12kx2=12kxo2\frac{1}{2}mv^2+\frac{1}{2}kx^2=\frac{1}{2}kx_o^2
Giancoli 6th Edition, Chapter 6, Problem 41 solution video poster
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VIDEO TRANSCRIPT

The total kinetic, and potential energy of this system with this spring being compressed a distance 'x' naught, is kinetic energy plus potential energy, is one half 'mv' squared, whatever it's speed happens to be at a certain position, plus one half 'kx' squared. So that's the elastic potential energy here, and the kinetic energy there. And this total will be, one half 'kx' knot squared, where 'x' knot is the initial starting compression position. More could have been stretched too, for that matter and it would be the same.

COMMENTS
By vgrove on Tue, 10/16/2012 - 5:51 PM

You are wonderful! This has been such a help-I actually enjoy physics because of your explanations-thank you so much :)

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